What is the total capacitance when connecting three capacitors of 0.05 uF, 20 uF, and 40 uF in series?

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To determine the total capacitance when capacitors are connected in series, one must use the formula:

1/C_total = 1/C1 + 1/C2 + 1/C3,

where C1, C2, and C3 are the capacitances of the individual capacitors.

In this case, the capacitors have the following values:

Applying the formula, we compute:

1/C_total = 1/0.05 + 1/20 + 1/40.

Calculating each term separately:

1/0.05 = 20,

1/20 = 0.05,

1/40 = 0.025.

Now, summing these values:

1/C_total = 20 + 0.05 + 0.025 = 20.075.

Next, we take the reciprocal to find C_total:

C_total = 1 / 20.075 ≈ 0.0498 µF.

Thus, the total capacitance when 0.05 µF, 20 µF, and 40 µF capacitors are connected in