What is the total capacitance of three capacitors in parallel with values of 470 pf, 560 pf, and 0.47 pf?

Prepare for the Associate Certified Electronic Technician Exam. Utilize flashcards and multiple choice questions with detailed explanations to enhance your understanding. Excel in your upcoming exam!

The total capacitance of capacitors connected in parallel is calculated by simply summing their capacitance values. In this case, you have three capacitors with values of 470 picofarads (pf), 560 picofarads (pf), and 0.47 picofarads (pf).

To find the total capacitance, you add these values together:

  1. Start by converting the values into the same unit for clarity. Notably, 0.47 picofarads is essentially 0.47 pf, which is already in the correct unit.

  2. Now, perform the addition:

  • 470 pf + 560 pf + 0.47 pf = 1030.47 pf.

Therefore, the correct total capacitance is 1030.47 picofarads. This aligns perfectly with the first choice, reinforcing the accurate methodology of summing capacitance values in parallel circuits.

The context of the other choices highlights that while some options might seem close, they either present incorrect units or values that do not reflect the summation of the specified capacitors. For example, microfarads (uF) is a different measurement unit entirely and not applicable here, while rounding errors might lead to misleading figures

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