What is the average of a full sine wave rectified voltage expressed as a fraction of its peak value?

The average voltage of a full sine wave that has been rectified can be calculated based on its peak value. For a full sine wave, rectification involves removing the negative half of the waveform, leading to a waveform that oscillates from zero to the peak value.

The formula for the average value of a full sine wave (after rectification) is given by:

[ V_{avg} = \frac{2}{\pi} \cdot V_{peak} ]

When evaluating this expression, we can approximate the numerical value:

[ \frac{2}{\pi} \approx 0.637 ]

Thus, the average voltage of a full sine wave rectified voltage is approximately 0.637 times its peak value. This results in the correct answer, which accurately reflects the relationship between the average rectified voltage and its peak amplitude.