In the binary number 100000, what weight does the "1" carry?

In the binary system, each digit has a specific weight that is determined by its position. The rightmost digit represents (2^0) (1), the next represents (2^1) (2), then (2^2) (4), and so on, moving leftward. In the binary number 100000, the "1" is in the 6th position from the right, corresponding to (2^5).

Calculating (2^5) gives us 32. Therefore, the "1" in the binary number 100000 carries a weight of 32, since it represents (1 \times 32) with all other digits being zero, contributing nothing to the total value. This is essential to understand when interpreting binary numbers, as it lays the foundation for converting binary to decimal accurately.